What is the integral from 0 to 1 of 2(3x+2)^3 ?

The integral from 0 to 1 of 2(3x+2)^3 is 203/2

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integral from 0 to 1 of 2(3x+2)^3

\int_{0}^{1} 2 (3 x + 2)^{3} d x

\frac{203}{2}

Decimal Notation

101.5

Solution steps

\int_{0}^{1} 2 (3 x + 2)^{3} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int_{0}^{1} (3 x + 2)^{3} d x

Apply u-substitution

: \int_{2}^{5} \frac{u ^{3}}{3} d u

= 2 \cdot \int_{2}^{5} \frac{u ^{3}}{3} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \frac{1}{3} \cdot \int_{2}^{5} u^{3} d u

Apply the Power Rule

: [\frac{u ^{4}}{4}]_{2}^{5}

= 2 \cdot \frac{1}{3} [\frac{u ^{4}}{4}]_{2}^{5}

Simplify

2 \cdot \frac{1}{3} [\frac{u ^{4}}{4}]_{2}^{5} : \frac{2}{3} [\frac{u ^{4}}{4}]_{2}^{5}

= \frac{2}{3} [\frac{u ^{4}}{4}]_{2}^{5}

Compute the boundaries:

\frac{609}{4}

= \frac{2}{3} \cdot \frac{609}{4}

Simplify

= \frac{203}{2}

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What is the integral from 0 to 1 of 2(3x+2)^3 ?
The integral from 0 to 1 of 2(3x+2)^3 is 203/2