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Popular >

integral from 0 to 4 of (4-y^2)

Solution

\int_{0}^{4} (4 - y^{2}) d y

Solution

- \frac{16}{3}

+1

Solution steps

\int_{0}^{4} 4 - y^{2} d y

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{4} 4 d y - \int_{0}^{4} y^{2} d y

\int_{0}^{4} 4 d y = 16

\int_{0}^{4} y^{2} d y = \frac{64}{3}

= 16 - \frac{64}{3}

Simplify

16 - \frac{64}{3} : - \frac{16}{3}

= - \frac{16}{3}

Popular Examples

integral from-1 to 1 of t*sin(npit)

\int_{- 1}^{1} t \cdot sin (nπ t) d t

integral from 0 to pi/4 of e^xsin(x)

\int_{0}^{\frac{π}{4}} e^{x} sin (x) d x

integral from 2 to 10 of 1/48 x

\int_{2}^{10} \frac{1}{48} x d x

integral from 2 to 5 of 1/((x-2))

\int_{2}^{5} \frac{1}{( x - 2 )} d x

integral from 0 to pi/2 of sec(x)-tan(x)

\int_{0}^{\frac{π}{2}} sec (x) - tan (x) d x

Frequently Asked Questions (FAQ)

What is the integral from 0 to 4 of (4-y^2) ?
The integral from 0 to 4 of (4-y^2) is -16/3