What is the integral from 0 to 4 of 4e^x ?

The integral from 0 to 4 of 4e^x is 4(e^4-1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 4 of 4e^x

\int_{0}^{4} 4 e^{x} d x

4 (e^{4} - 1)

Decimal Notation

214.39260 \dots

Solution steps

\int_{0}^{4} 4 e^{x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \int_{0}^{4} e^{x} d x

Use the common integral:

\int e^{x} d x = e^{x}

= 4 [e^{x}]_{0}^{4}

Compute the boundaries:

e^{4} - 1

= 4 (e^{4} - 1)

\int_{- 1}^{- 4} (2 e^{x} + 5) d x

\int_{x}^{x} x d x

\int_{- 1}^{x} x + 1 d x

\int_{2}^{4} (x)^{2} d x

\int_{- π}^{0} (π + t) cos (n t) d t

What is the integral from 0 to 4 of 4e^x ?
The integral from 0 to 4 of 4e^x is 4(e^4-1)