What is the integral from 0 to 4 of 4e^x ?

The integral from 0 to 4 of 4e^x is 4(e^4-1)

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integral from 0 to 4 of 4e^x

\int_{0}^{4} 4 e^{x} d x

4 (e^{4} - 1)

Solution steps

\int_{0}^{4} 4 e^{x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \int_{0}^{4} e^{x} d x

Use the common integral:

\int e^{x} d x = e^{x}

= 4 [e^{x}]_{0}^{4}

Compute the boundaries:

e^{4} - 1

= 4 (e^{4} - 1)

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\int_{- 1}^{x} x + 1 d x

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\int_{- π}^{0} (π + t) cos (n t) d t

What is the integral from 0 to 4 of 4e^x ?
The integral from 0 to 4 of 4e^x is 4(e^4-1)