What is the integral from 2 to 4 of (sqrt(x))^2 ?

The integral from 2 to 4 of (sqrt(x))^2 is 6

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integral from 2 to 4 of (sqrt(x))^2

\int_{2}^{4} (x)^{2} d x

6

Solution steps

\int_{2}^{4} (x)^{2} d x

Simplify

(x)^{2} : x

= \int_{2}^{4} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{2}^{4}

= [\frac{x ^{2}}{2}]_{2}^{4}

Compute the boundaries:

6

= 6

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What is the integral from 2 to 4 of (sqrt(x))^2 ?
The integral from 2 to 4 of (sqrt(x))^2 is 6