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Popular >

y^'+1/x y=5x^2

Solution

y^{^{'}} + \frac{1}{x} y = 5 x^{2}

Solution

y = \frac{5 x ^{3}}{4} + \frac{c _{1}}{x}

Solution steps

y^{'} (x) + \frac{1}{x} y = 5 x^{2}

Solve linear ODE:

y = \frac{5 x ^{3}}{4} + \frac{c _{1}}{x}

y = \frac{5 x ^{3}}{4} + \frac{c _{1}}{x}

Popular Examples

2y^{''}+26y=0,y(0)=9,y^'(0)=5

2 y^{^{''}} + 26 y = 0, y (0) = 9, y^{^{'}} (0) = 5

(\partial)/(\partial x)(9x^2+25y^2-225)

\frac{\partial}{\partial x} (9 x^{2} + 25 y^{2} - 225)

implicit (dy)/(dx),6x^3+7y^3=13xy implicit derivative

\frac{d y}{d x}, 6 x^{3} + 7 y^{3} = 13 x y

slope ofintercept (-1.4)(1.4)slope intercept

(- 1.4) (1.4)

derivative of 2arctan(x)-x derivative of

2 arctan (x) - x

Frequently Asked Questions (FAQ)

What is the solution for y^'+1/x y=5x^2 ?
The solution for y^'+1/x y=5x^2 is y=(5x^3)/4+(c_{1})/x