What is the integral from 0 to pi/2 of 2-2sin(x) ?

The integral from 0 to pi/2 of 2-2sin(x) is pi-2

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integral from 0 to pi/2 of 2-2sin(x)

\int_{0}^{\frac{π}{2}} 2 - 2 sin (x) d x

π - 2

Solution steps

\int_{0}^{\frac{π}{2}} 2 - 2 sin (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{\frac{π}{2}} 2 d x - \int_{0}^{\frac{π}{2}} 2 sin (x) d x

\int_{0}^{\frac{π}{2}} 2 d x = π

\int_{0}^{\frac{π}{2}} 2 sin (x) d x = 2

= π - 2

\int_{0}^{2} 3 x x^{2} + 4 a^{2} d x

\int_{- 2}^{2} 1 - x^{2} d y

\int_{0}^{1} \frac{1}{2} x^{3} + 2 d x

\int_{2}^{4} e^{2 x} d x

\int_{\frac{1}{2}}^{1} x (e - e^{x}) d x

What is the integral from 0 to pi/2 of 2-2sin(x) ?
The integral from 0 to pi/2 of 2-2sin(x) is pi-2