What is the integral from 9 to 100 of 1x^{-2} ?

The integral from 9 to 100 of 1x^{-2} is 91/900

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integral from 9 to 100 of 1x^{-2}

\int_{9}^{100} 1 x^{- 2} d x

\frac{91}{900}

Solution steps

\int_{9}^{100} 1 \cdot x^{- 2} d x

Simplify

1 \cdot x^{- 2} : \frac{1}{x ^{2}}

= \int_{9}^{100} \frac{1}{x ^{2}} d x

Apply the Power Rule

: [- \frac{1}{x}]_{9}^{100}

= [- \frac{1}{x}]_{9}^{100}

Compute the boundaries:

\frac{91}{900}

= \frac{91}{900}

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What is the integral from 9 to 100 of 1x^{-2} ?
The integral from 9 to 100 of 1x^{-2} is 91/900