What is the integral from 0 to 25 of sin(x) ?

The integral from 0 to 25 of sin(x) is -cos(25)+1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 25 of sin(x)

\int_{0}^{25} sin (x) d x

- cos (25) + 1

Solution steps

\int_{0}^{25} sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= [- cos (x)]_{0}^{25}

Compute the boundaries:

- cos (25) + 1

= - cos (25) + 1

\int_{2}^{3} x^{3} + x d x

\int_{0}^{4} (1 + \frac{x}{2}) d x

\int_{1}^{4} \frac{u - 5}{u} d u

\int_{- 1}^{3} \frac{x ^{3} - 1}{x ^{3} + x} d x

\int_{0}^{2} 6 x^{5} e^{x^{3} y} d y

What is the integral from 0 to 25 of sin(x) ?
The integral from 0 to 25 of sin(x) is -cos(25)+1