What is the integral from 6 to 10 of 2x^{-3} ?

The integral from 6 to 10 of 2x^{-3} is 4/225

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integral from 6 to 10 of 2x^{-3}

\int_{6}^{10} 2 x^{- 3} d x

\frac{4}{225}

Solution steps

\int_{6}^{10} 2 x^{- 3} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int_{6}^{10} x^{- 3} d x

Apply the Power Rule

: [- \frac{1}{2 x ^{2}}]_{6}^{10}

= 2 [- \frac{1}{2 x ^{2}}]_{6}^{10}

Compute the boundaries:

\frac{2}{225}

= 2 \cdot \frac{2}{225}

Simplify

= \frac{4}{225}

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\int_{- 1}^{1} 3 x^{2} + 4 d x

\int_{0}^{2} x - 3 y^{2} d x

What is the integral from 6 to 10 of 2x^{-3} ?
The integral from 6 to 10 of 2x^{-3} is 4/225