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Popular >

integral from 0 to 4 of 15-2x-7

Solution

\int_{0}^{4} 15 - 2 x - 7 d x

Solution

16

Solution steps

\int_{0}^{4} 15 - 2 x - 7 d x

Simplify

= \int_{0}^{4} - 2 x + 8 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{0}^{4} 2 x d x + \int_{0}^{4} 8 d x

\int_{0}^{4} 2 x d x = 16

\int_{0}^{4} 8 d x = 32

= - 16 + 32

Simplify

= 16

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\int_{1}^{4} \frac{1 + t}{t} d t

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\int_{0}^{5} x e^{x - 5} d x

integral from-1 to 0 of x^5

\int_{- 1}^{0} x^{5} d x

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\int_{- c}^{c} \frac{3}{2} x^{2} d x

integral from 1 to sqrt(2 of)x6^{(x^2)}

\int_{1}^{2} x 6^{(x^{2})} d x

Frequently Asked Questions (FAQ)

What is the integral from 0 to 4 of 15-2x-7 ?
The integral from 0 to 4 of 15-2x-7 is 16