What is the integral from 0^+to 1 of 1/(x^2) ?

The integral from 0^+to 1 of 1/(x^2) is diverges

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integral from 0^+to 1 of 1/(x^2)

\int_{0^{+}}^{1} \frac{1}{x ^{2}} d x

diverges

Solution steps

\int_{0^{+}}^{1} \frac{1}{x ^{2}} d x

Apply the Power Rule

: [- \frac{1}{x}]_{0^{+}}^{1}

= [- \frac{1}{x}]_{0^{+}}^{1}

Simplify

= [- \frac{1}{x}]_{0}^{1}

Compute the boundaries:

diverges

= diverges

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What is the integral from 0^+to 1 of 1/(x^2) ?
The integral from 0^+to 1 of 1/(x^2) is diverges