What is the integral from-3 to 3 of x/(1+x^2) ?

The integral from-3 to 3 of x/(1+x^2) is 0

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integral from-3 to 3 of x/(1+x^2)

\int_{- 3}^{3} \frac{x}{1 + x ^{2}} d x

0

Solution steps

\int_{- 3}^{3} \frac{x}{1 + x ^{2}} d x

If f(x) is an odd function and continuous at:

[- a, a]

then

\int_{- a}^{a} f (x) d x = 0

Parity of

\frac{x}{1 + x ^{2}} :

Odd

= 0

\int_{0}^{1} (- x^{2} - x + 2) d x

\int_{0}^{π} e^{- \frac{t}{2}} d t

\int_{0}^{2} x^{2} + k x + 1 d x

\int_{0}^{1} \frac{x ^{2} + x}{x} d x

\int_{- \infty}^{0} e^{12 x} d x

What is the integral from-3 to 3 of x/(1+x^2) ?
The integral from-3 to 3 of x/(1+x^2) is 0