What is the integral from 0 to 1 of x^{y+1} ?

The integral from 0 to 1 of x^{y+1} is 1/(y+2)

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integral from 0 to 1 of x^{y+1}

\int_{0}^{1} x^{y + 1} d x

\frac{1}{y + 2}

Solution steps

\int_{0}^{1} x^{y + 1} d x

Apply the Power Rule

: [\frac{x ^{y + 2}}{y + 2}]_{0}^{1}

= [\frac{x ^{y + 2}}{y + 2}]_{0}^{1}

Compute the boundaries:

\frac{1}{y + 2}

= \frac{1}{y + 2}

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What is the integral from 0 to 1 of x^{y+1} ?
The integral from 0 to 1 of x^{y+1} is 1/(y+2)