What is the integral from 1 to 2 of u^2 ?

The integral from 1 to 2 of u^2 is 7/3

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integral from 1 to 2 of u^2

\int_{1}^{2} u^{2} d u

\frac{7}{3}

Solution steps

\int_{1}^{2} u^{2} d u

Apply the Power Rule

: [\frac{u ^{3}}{3}]_{1}^{2}

= [\frac{u ^{3}}{3}]_{1}^{2}

Compute the boundaries:

\frac{7}{3}

= \frac{7}{3}

\int_{0}^{4} (x^{2} + 9 x) d x

\int_{0}^{3} x \frac{x ^{2}}{9} d x

\int_{2}^{3} \frac{1}{x ^{4}} d x

\int_{2}^{4} x^{2} e^{x^{3} + 5} d x

\int_{- 1}^{5} (4 x^{3} - 3 x^{2} + 1) x d x

What is the integral from 1 to 2 of u^2 ?
The integral from 1 to 2 of u^2 is 7/3