What is the integral from 2 to 3 of e^t ?

The integral from 2 to 3 of e^t is e^3-e^2

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integral from 2 to 3 of e^t

\int_{2}^{3} e^{t} d t

e^{3} - e^{2}

Solution steps

\int_{2}^{3} e^{t} d t

Use the common integral:

\int e^{t} d t = e^{t}

= [e^{t}]_{2}^{3}

Compute the boundaries:

e^{3} - e^{2}

= e^{3} - e^{2}

\int_{0}^{1} (- y - \frac{1}{2} e^{y}) d y

\int_{- 1}^{3} 1 + (2 y + 3)^{2} d y

\int_{0}^{b} (a - a \frac{x}{b}) d x

\int_{- 1}^{1} x \frac{3}{4} (1 - x^{2}) d x

\int_{0}^{1} (3 x^{2} - 2 x)^{2} d x

What is the integral from 2 to 3 of e^t ?
The integral from 2 to 3 of e^t is e^3-e^2