What is the integral from e to 2e of xln(x^3) ?

The integral from e to 2e of xln(x^3) is (24e^2ln(2e)-15e^2)/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from e to 2e of xln(x^3)

\int_{e}^{2 e} x ln (x^{3}) d x

\frac{24 e ^{2} ln ( 2 e ) - 15 e ^{2}}{4}

Solution steps

\int_{e}^{2 e} x ln (x^{3}) d x

Apply Integration By Parts

: [\frac{1}{2} (x^{2} ln (x^{3}) - 2 \cdot \int \frac{3 x}{2} d x)]_{e}^{2 e}

= [\frac{1}{2} (x^{2} ln (x^{3}) - 2 \cdot \int \frac{3 x}{2} d x)]_{e}^{2 e}

\int \frac{3 x}{2} d x = \frac{3 x ^{2}}{4}

= [\frac{1}{2} (x^{2} ln (x^{3}) - 2 \cdot \frac{3 x ^{2}}{4})]_{e}^{2 e}

Simplify

[\frac{1}{2} (x^{2} ln (x^{3}) - 2 \cdot \frac{3 x ^{2}}{4})]_{e}^{2 e} : [\frac{1}{2} (3 x^{2} ln (x) - \frac{3 x ^{2}}{2})]_{e}^{2 e}

= [\frac{1}{2} (3 x^{2} ln (x) - \frac{3 x ^{2}}{2})]_{e}^{2 e}

Compute the boundaries:

\frac{24 e ^{2} ln ( 2 e ) - 15 e ^{2}}{4}

= \frac{24 e ^{2} ln ( 2 e ) - 15 e ^{2}}{4}

\int_{7}^{\infty} \frac{7}{x ^{3}} d x

\int_{0}^{0} x d x

\int_{0}^{\frac{π}{2}} (2 sin (2 x)) d x

\int_{- 1}^{1} π (x^{2} - 1)^{2} d x

\int_{0}^{π} 3 x^{2} sin (x^{3}) d x

What is the integral from e to 2e of xln(x^3) ?
The integral from e to 2e of xln(x^3) is (24e^2ln(2e)-15e^2)/4