What is the integral from 4 to infinity of 8x^{-2} ?

The integral from 4 to infinity of 8x^{-2} is 2

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integral from 4 to infinity of 8x^{-2}

\int_{4}^{\infty} 8 x^{- 2} d x

2

Solution steps

\int_{4}^{\infty} 8 x^{- 2} d x

Compute the indefinite integral:

\int 8 x^{- 2} d x = - \frac{8}{x} + C

Compute the boundaries:

\int_{4}^{\infty} 8 x^{- 2} d x = 0 - (- 2)

= 0 - (- 2)

Simplify

= 2

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What is the integral from 4 to infinity of 8x^{-2} ?
The integral from 4 to infinity of 8x^{-2} is 2