integral from (-pi)/2 to pi/2 of g(x)

해법

\int_{\frac{- π}{2}}^{\frac{π}{2}} g (x) d x

0

솔루션 단계

\int_{\frac{- π}{2}}^{\frac{π}{2}} gx d x

정수를 빼라:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= g \cdot \int_{\frac{- π}{2}}^{\frac{π}{2}} x d x

전원 규칙 적용

: [\frac{x ^{2}}{2}]_{\frac{- π}{2}}^{\frac{π}{2}}

= g [\frac{x ^{2}}{2}]_{\frac{- π}{2}}^{\frac{π}{2}}

단순화

= g [\frac{x ^{2}}{2}]_{- \frac{π}{2}}^{\frac{π}{2}}

경계 계산:

0

= g \cdot 0

단순화

= 0