What is the integral from 0 to 1 of (2x^2+3x-4) ?

The integral from 0 to 1 of (2x^2+3x-4) is -11/6

Popular >

integral from 0 to 1 of (2x^2+3x-4)

\int_{0}^{1} (2 x^{2} + 3 x - 4) d x

- \frac{11}{6}

Solution steps

\int_{0}^{1} 2 x^{2} + 3 x - 4 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} 2 x^{2} d x + \int_{0}^{1} 3 x d x - \int_{0}^{1} 4 d x

\int_{0}^{1} 2 x^{2} d x = \frac{2}{3}

\int_{0}^{1} 3 x d x = \frac{3}{2}

\int_{0}^{1} 4 d x = 4

= \frac{2}{3} + \frac{3}{2} - 4

Simplify

\frac{2}{3} + \frac{3}{2} - 4 : - \frac{11}{6}

= - \frac{11}{6}

\int_{x^{2} + 3}^{4 x} 1 d y

\int_{0}^{3} x (1.33 x^{2} - 3) d x

\int_{1}^{7} e^{x} d x

\int_{1}^{4} x ln (2) - \frac{3}{2 x} d x

\int_{2}^{10} (5 x^{2} - 2) d x

What is the integral from 0 to 1 of (2x^2+3x-4) ?
The integral from 0 to 1 of (2x^2+3x-4) is -11/6