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Popular >

integral from 0 to 3 of (-x^2+4)

Solution

\int_{0}^{3} (- x^{2} + 4) d x

Solution

3

Solution steps

\int_{0}^{3} - x^{2} + 4 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{0}^{3} x^{2} d x + \int_{0}^{3} 4 d x

\int_{0}^{3} x^{2} d x = 9

\int_{0}^{3} 4 d x = 12

= - 9 + 12

Simplify

= 3

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Frequently Asked Questions (FAQ)

What is the integral from 0 to 3 of (-x^2+4) ?
The integral from 0 to 3 of (-x^2+4) is 3