What is the integral from-9 to 0 of (y/9+sqrt(y+10)) ?

The integral from-9 to 0 of (y/9+sqrt(y+10)) is -9/2+(20sqrt(10)-2)/3

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integral from-9 to 0 of (y/9+sqrt(y+10))

\int_{- 9}^{0} (\frac{y}{9} + y + 10) d y

- \frac{9}{2} + \frac{20 10 - 2}{3}

Solution steps

\int_{- 9}^{0} \frac{y}{9} + y + 10 d y

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 9}^{0} \frac{y}{9} d y + \int_{- 9}^{0} y + 10 d y

\int_{- 9}^{0} \frac{y}{9} d y = - \frac{9}{2}

\int_{- 9}^{0} y + 10 d y = \frac{20 10 - 2}{3}

= - \frac{9}{2} + \frac{20 10 - 2}{3}

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What is the integral from-9 to 0 of (y/9+sqrt(y+10)) ?
The integral from-9 to 0 of (y/9+sqrt(y+10)) is -9/2+(20sqrt(10)-2)/3