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Popular >

integral from 2 to 6 of (x^2-4x)

Solution

\int_{2}^{6} (x^{2} - 4 x) d x

Solution

\frac{16}{3}

+1

Solution steps

\int_{2}^{6} x^{2} - 4 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{2}^{6} x^{2} d x - \int_{2}^{6} 4 x d x

\int_{2}^{6} x^{2} d x = \frac{208}{3}

\int_{2}^{6} 4 x d x = 64

= \frac{208}{3} - 64

Simplify

\frac{208}{3} - 64 : \frac{16}{3}

= \frac{16}{3}

Popular Examples

integral from 1 to 2 of xsqrt(x^2-2)

\int_{1}^{2} x x^{2} - 2 d x

integral from 1 to x of ln(y)

\int_{1}^{x} ln (y) d y

integral from 0 to 1/2 of (cos(pix)-2^x)

\int_{0}^{\frac{1}{2}} (cos (π x) - 2^{x}) d x

integral from 0 to 1 of (e^t-e+1)^2

\int_{0}^{1} (e^{t} - e + 1)^{2} d t

integral from 0 to 1 of sqrt(1)

\int_{0}^{1} 1

Frequently Asked Questions (FAQ)

What is the integral from 2 to 6 of (x^2-4x) ?
The integral from 2 to 6 of (x^2-4x) is 16/3