What is the integral from 1 to 0 of 1/(x^2) ?

The integral from 1 to 0 of 1/(x^2) is diverges

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integral from 1 to 0 of 1/(x^2)

\int_{1}^{0} \frac{1}{x ^{2}} d x

diverges

Solution steps

\int_{1}^{0} \frac{1}{x ^{2}} d x

\int_{a}^{b} f (x) d x = - \int_{b}^{a} f (x) d x, a < b

= - \int_{0}^{1} \frac{1}{x ^{2}} d x

Apply the Power Rule

: [- \frac{1}{x}]_{0}^{1}

= - [- \frac{1}{x}]_{0}^{1}

Compute the boundaries:

diverges

= diverges

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What is the integral from 1 to 0 of 1/(x^2) ?
The integral from 1 to 0 of 1/(x^2) is diverges