What is the integral from 1 to sin(x) of cos(x) ?

The integral from 1 to sin(x) of cos(x) is sin(sin(x))-sin(1)

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integral from 1 to sin(x) of cos(x)

\int_{1}^{s i n (x)} cos (x) d x

sin (sin (x)) - sin (1)

Solution steps

\int_{1}^{s i n (x)} cos (x) d x

Use the common integral:

\int cos (x) d x = sin (x)

= [sin (x)]_{1}^{s i n (x)}

Compute the boundaries:

sin (sin (x)) - sin (1)

= sin (sin (x)) - sin (1)

\int_{0}^{x} - sin (π \cdot x) d x

\int_{0}^{1} - 2 sin^{2} (2 - 2 t) d t

\int_{- 1}^{3} \frac{1}{2} x^{2} - 2 x - 3 d x

\int_{0}^{1} x y e^{y^{2} x} d y

\int_{0}^{0.5} C x d x

What is the integral from 1 to sin(x) of cos(x) ?
The integral from 1 to sin(x) of cos(x) is sin(sin(x))-sin(1)