What is the integral from x^2+2 to 3x of 1 ?

The integral from x^2+2 to 3x of 1 is 3x-x^2-2

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integral from x^2+2 to 3x of 1

\int_{x^{2} + 2}^{3 x} 1 d y

3 x - x^{2} - 2

Solution steps

\int_{x^{2} + 2}^{3 x} 1 d y

Integral of a constant:

\int a d x = a x

= [1 \cdot y]_{x^{2} + 2}^{3 x}

Simplify

= [y]_{x^{2} + 2}^{3 x}

Compute the boundaries:

3 x - x^{2} - 2

= 3 x - x^{2} - 2

\int_{- 2}^{2} \frac{1}{- 2 ( 1 + x )} d x

\int_{0}^{1} (2 - x - \frac{2}{x + 1}) d x

\int_{0}^{4} x^{3} - x^{2} + 1 d x

\int_{1}^{4} - x^{2} + 8 x d x

\int_{0}^{π} 2 e^{x} sin (x) d x

What is the integral from x^2+2 to 3x of 1 ?
The integral from x^2+2 to 3x of 1 is 3x-x^2-2