What is the integral from 0 to 1 of (e^x-x^2) ?

The integral from 0 to 1 of (e^x-x^2) is e-4/3

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integral from 0 to 1 of (e^x-x^2)

\int_{0}^{1} (e^{x} - x^{2}) d x

e - \frac{4}{3}

Solution steps

\int_{0}^{1} e^{x} - x^{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} e^{x} d x - \int_{0}^{1} x^{2} d x

\int_{0}^{1} e^{x} d x = e - 1

\int_{0}^{1} x^{2} d x = \frac{1}{3}

= e - 1 - \frac{1}{3}

Combine the fractions

- 1 - \frac{1}{3} : - \frac{4}{3}

= e - \frac{4}{3}

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What is the integral from 0 to 1 of (e^x-x^2) ?
The integral from 0 to 1 of (e^x-x^2) is e-4/3