What is the integral from 1 to 9 of 5/t ?

The integral from 1 to 9 of 5/t is 10ln(3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 1 to 9 of 5/t

\int_{1}^{9} \frac{5}{t} d t

10 ln (3)

Decimal Notation

10.98612 \dots

Solution steps

\int_{1}^{9} \frac{5}{t} d t

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 5 \cdot \int_{1}^{9} \frac{1}{t} d t

Use the common integral:

\int \frac{1}{t} d t = ln (∣ t ∣)

= 5 [ln ∣ t ∣]_{1}^{9}

Compute the boundaries:

2 ln (3)

= 5 \cdot 2 ln (3)

Simplify

= 10 ln (3)

\int_{- 2}^{3} (8 - x^{2}) - (- x + 2) d x

\int_{1}^{4} X^{2} d X

\int_{0}^{9} 8 x d x

\int_{2}^{10} k x^{- 3} d x

\int_{0}^{6 π} θ θ^{2} + 4 d θ

What is the integral from 1 to 9 of 5/t ?
The integral from 1 to 9 of 5/t is 10ln(3)