What is the integral from 1 to 4 of (x-2)^4 ?

The integral from 1 to 4 of (x-2)^4 is 33/5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 1 to 4 of (x-2)^4

\int_{1}^{4} (x - 2)^{4} d x

\frac{33}{5}

Decimal Notation

6.6

Solution steps

\int_{1}^{4} (x - 2)^{4} d x

Apply u-substitution

: \int_{- 1}^{2} u^{4} d u

= \int_{- 1}^{2} u^{4} d u

Apply the Power Rule

: [\frac{u ^{5}}{5}]_{- 1}^{2}

= [\frac{u ^{5}}{5}]_{- 1}^{2}

Compute the boundaries:

\frac{33}{5}

= \frac{33}{5}

\int_{5}^{\infty} e^{- 2 x} d x

\int_{- 2}^{3} x + 2 d x

\int_{1}^{4} (\frac{3}{x ^{2}} - 1) d x

\int_{\frac{3}{2}}^{2} \frac{3}{8} x^{2} d x

\int_{- 1}^{2} x e^{- x^{2}} d x

What is the integral from 1 to 4 of (x-2)^4 ?
The integral from 1 to 4 of (x-2)^4 is 33/5