What is the integral from 0 to pi/2 of (cos(x)-1) ?

The integral from 0 to pi/2 of (cos(x)-1) is 1-pi/2

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integral from 0 to pi/2 of (cos(x)-1)

\int_{0}^{\frac{π}{2}} (cos (x) - 1) d x

1 - \frac{π}{2}

Decimal Notation

- 0.57079 \dots

Solution steps

\int_{0}^{\frac{π}{2}} cos (x) - 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{\frac{π}{2}} cos (x) d x - \int_{0}^{\frac{π}{2}} 1 d x

\int_{0}^{\frac{π}{2}} cos (x) d x = 1

\int_{0}^{\frac{π}{2}} 1 d x = \frac{π}{2}

= 1 - \frac{π}{2}

\int_{- 1}^{1} (\frac{x ^{3} - 8}{x - 2}) d x

\int_{- 1}^{1} x^{2} + 2 d x

\int_{0.5}^{0} x d x

\int_{2}^{5} 6 x^{- 2} d x

\int_{4}^{7} e^{2 x + 1} d x

What is the integral from 0 to pi/2 of (cos(x)-1) ?
The integral from 0 to pi/2 of (cos(x)-1) is 1-pi/2