What is (\partial)/(\partial x)(-7x^2-5y^2+xy) ?

The answer to (\partial)/(\partial x)(-7x^2-5y^2+xy) is y-14x

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(\partial)/(\partial x)(-7x^2-5y^2+xy)

\frac{\partial}{\partial x} (- 7 x^{2} - 5 y^{2} + x y)

y - 14 x

Solution steps

\frac{\partial}{\partial x} (- 7 x^{2} - 5 y^{2} + x y)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{\partial}{\partial x} (7 x^{2}) - \frac{\partial}{\partial x} (5 y^{2}) + \frac{\partial}{\partial x} (x y)

\frac{\partial}{\partial x} (7 x^{2}) = 14 x

\frac{\partial}{\partial x} (5 y^{2}) = 0

\frac{\partial}{\partial x} (x y) = y

= - 14 x - 0 + y

Simplify

= y - 14 x

\frac{( 4 s ^{3} )}{( s + 5 ) ^{9}}

x \to 0 lim (ln (1 - 3 x))

\int (e^{- x} - e^{3}) \cdot (e^{x} + e^{- 5}) d x

y^{^{'}} + y \cdot tan (x) = \frac{1}{cos ( x )}

ln (1 + 12 x)

What is (\partial)/(\partial x)(-7x^2-5y^2+xy) ?
The answer to (\partial)/(\partial x)(-7x^2-5y^2+xy) is y-14x