What is the solution for (2x+y+1)((dy)/(dx))=1 ?

The solution for (2x+y+1)((dy)/(dx))=1 is y=-(\W((c_{1})/(e^{4x+3)}))/2-2x-3/2

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(2x+y+1)((dy)/(dx))=1

(2 x + y + 1) (\frac{d y}{d x}) = 1

y = - \frac{W ( \frac{c _{1}}{e ^{4 x + 3}} )}{2} - 2 x - \frac{3}{2}

Solution steps

(2 x + y + 1) (\frac{d y}{d x}) = 1

Solve exact ODE:

y = - \frac{W ( \frac{c _{1}}{e ^{4 x + 3}} )}{2} - 2 x - \frac{3}{2}

y = - \frac{W ( \frac{c _{1}}{e ^{4 x + 3}} )}{2} - 2 x - \frac{3}{2}

f (x) = \frac{32}{- 4}

\int_{3}^{4} 3 x cos (x^{2}) d x

\int (3 x + 1)^{3} d x

- 3 x^{2}

\frac{d}{d x} (2 x^{2} - 4 x y + 3 y^{2} + 6 z^{2})

What is the solution for (2x+y+1)((dy)/(dx))=1 ?
The solution for (2x+y+1)((dy)/(dx))=1 is y=-(\W((c_{1})/(e^{4x+3)}))/2-2x-3/2