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Popular >

d/(d{x)}(2{x}^2-4{x}{y}+3{y}^2+6{z}^2)

Solution

\frac{d}{d x} (2 x^{2} - 4 x y + 3 y^{2} + 6 z^{2})

Solution

4 x - 4 y

Solution steps

\frac{d}{d x} (2 x^{2} - 4 x y + 3 y^{2} + 6 z^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) - \frac{d}{d x} (4 x y) + \frac{d}{d x} (3 y^{2}) + \frac{d}{d x} (6 z^{2})

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (4 x y) = 4 y

\frac{d}{d x} (3 y^{2}) = 0

\frac{d}{d x} (6 z^{2}) = 0

= 4 x - 4 y + 0 + 0

Simplify

= 4 x - 4 y

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Frequently Asked Questions (FAQ)

What is the d/(d{x)}(2{x}^2-4{x}{y}+3{y}^2+6{z}^2) ?
The d/(d{x)}(2{x}^2-4{x}{y}+3{y}^2+6{z}^2) is 4{x}-4{y}
What is the first d/(d{x)}(2{x}^2-4{x}{y}+3{y}^2+6{z}^2) ?
The first d/(d{x)}(2{x}^2-4{x}{y}+3{y}^2+6{z}^2) is 4{x}-4{y}