What is the derivative of-x^2+4x ?

The derivative of-x^2+4x is -2x+4

What is the first derivative of-x^2+4x ?

The first derivative of-x^2+4x is -2x+4

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\frac{d}{d x} (- x^{2} + 4 x)

- 2 x + 4

Solution steps

\frac{d}{d x} (- x^{2} + 4 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (x^{2}) + \frac{d}{d x} (4 x)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (4 x) = 4

= - 2 x + 4

y = x (x - 10)

\frac{d}{d x} (\frac{x}{( x ^{2} + y ^{2} ) ^{2}})

\frac{d}{d t} (\frac{2}{t ^{2} + 2})

\int \frac{1}{- u ^{2} - a + b} d u

\frac{d}{d t} (tan (e^{6 t}) + e^{t a n (6 t)})

What is the derivative of-x^2+4x ?
The derivative of-x^2+4x is -2x+4
What is the first derivative of-x^2+4x ?
The first derivative of-x^2+4x is -2x+4