What is the d/(dt)(tan(e^{6t})+e^{tan(6t)}) ?

The d/(dt)(tan(e^{6t})+e^{tan(6t)}) is sec^2(e^{6t})e^{6t}*6+e^{tan(6t)}sec^2(6t)*6

What is the first d/(dt)(tan(e^{6t})+e^{tan(6t)}) ?

The first d/(dt)(tan(e^{6t})+e^{tan(6t)}) is sec^2(e^{6t})e^{6t}*6+e^{tan(6t)}sec^2(6t)*6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d t} (tan (e^{6 t}) + e^{t a n (6 t)})

sec^{2} (e^{6 t}) e^{6 t} \cdot 6 + e^{t a n (6 t)} sec^{2} (6 t) \cdot 6

Solution steps

\frac{d}{d t} (tan (e^{6 t}) + e^{t a n (6 t)})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (tan (e^{6 t})) + \frac{d}{d t} (e^{t a n (6 t)})

\frac{d}{d t} (tan (e^{6 t})) = sec^{2} (e^{6 t}) e^{6 t} \cdot 6

\frac{d}{d t} (e^{t a n (6 t)}) = e^{t a n (6 t)} sec^{2} (6 t) \cdot 6

= sec^{2} (e^{6 t}) e^{6 t} \cdot 6 + e^{t a n (6 t)} sec^{2} (6 t) \cdot 6

\frac{\partial}{\partial x} (cos (x y) + e^{yz} + ln (z x))

f^{9}

\frac{d y}{d x} = \frac{( 2 x + 1 )}{3 y}

\frac{d y}{d x} = 2 y - 4 x

f (x) = x^{2} (6 x + 1)^{3}

What is the d/(dt)(tan(e^{6t})+e^{tan(6t)}) ?
The d/(dt)(tan(e^{6t})+e^{tan(6t)}) is sec^2(e^{6t})e^{6t}*6+e^{tan(6t)}sec^2(6t)*6
What is the first d/(dt)(tan(e^{6t})+e^{tan(6t)}) ?
The first d/(dt)(tan(e^{6t})+e^{tan(6t)}) is sec^2(e^{6t})e^{6t}*6+e^{tan(6t)}sec^2(6t)*6