What is the derivative of f(x)=x^2(6x+1)^3 ?

The derivative of f(x)=x^2(6x+1)^3 is 2x(6x+1)^3+18(6x+1)^2x^2

What is the first derivative of f(x)=x^2(6x+1)^3 ?

The first derivative of f(x)=x^2(6x+1)^3 is 2x(6x+1)^3+18(6x+1)^2x^2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

f (x) = x^{2} (6 x + 1)^{3}

2 x (6 x + 1)^{3} + 18 (6 x + 1)^{2} x^{2}

Solution steps

\frac{d}{d x} (x^{2} (6 x + 1)^{3})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x^{2}, g = (6 x + 1)^{3}

= \frac{d}{d x} (x^{2}) (6 x + 1)^{3} + \frac{d}{d x} ((6 x + 1)^{3}) x^{2}

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} ((6 x + 1)^{3}) = 18 (6 x + 1)^{2}

= 2 x (6 x + 1)^{3} + 18 (6 x + 1)^{2} x^{2}

\int \frac{3}{x ^{- 1} + 1} d x

6 + 5 x

∣ x ∣, x^{2} - 2

1 - 9 x^{2} arccos (3 x)

n = 2 \sum \infty n

What is the derivative of f(x)=x^2(6x+1)^3 ?
The derivative of f(x)=x^2(6x+1)^3 is 2x(6x+1)^3+18(6x+1)^2x^2
What is the first derivative of f(x)=x^2(6x+1)^3 ?
The first derivative of f(x)=x^2(6x+1)^3 is 2x(6x+1)^3+18(6x+1)^2x^2