What is the solution for (y^'-e^{-t}+4)/y =-4,y(0)=-4 ?

The solution for (y^'-e^{-t}+4)/y =-4,y(0)=-4 is y= 1/(3e^t)-1-(10)/(3e^{4t)}

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(y^'-e^{-t}+4)/y =-4,y(0)=-4

\frac{y ^{^{'}} - e ^{- t} + 4}{y} = - 4, y (0) = - 4

y = \frac{1}{3 e ^{t}} - 1 - \frac{10}{3 e ^{4 t}}

Solution steps

\frac{y ^{'} ( t ) - e ^{- t} + 4}{y} = - 4

Solve linear ODE:

y = \frac{1}{3 e ^{t}} - 1 - \frac{10}{3 e ^{4 t}}

y = \frac{1}{3 e ^{t}} - 1 - \frac{10}{3 e ^{4 t}}

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What is the solution for (y^'-e^{-t}+4)/y =-4,y(0)=-4 ?
The solution for (y^'-e^{-t}+4)/y =-4,y(0)=-4 is y= 1/(3e^t)-1-(10)/(3e^{4t)}