What is the solution for (2y+1)dx+((x^2-y)/x)dy=0 ?

The solution for (2y+1)dx+((x^2-y)/x)dy=0 is y=x^2-sqrt(x^4+x^2-c_{1)},y=x^2+sqrt(x^4+x^2-c_{1)}

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(2y+1)dx+((x^2-y)/x)dy=0

(2 y + 1) d x + (\frac{x ^{2} - y}{x}) d y = 0

y = x^{2} - x^{4} + x^{2} - c_{1}, y = x^{2} + x^{4} + x^{2} - c_{1}

Solution steps

(2 y + 1) d x + (\frac{x ^{2} - y}{x}) d y = 0

Solve exact ODE:

y = x^{2} - x^{4} + x^{2} - c_{1}, y = x^{2} + x^{4} + x^{2} - c_{1}

y = x^{2} - x^{4} + x^{2} - c_{1}, y = x^{2} + x^{4} + x^{2} - c_{1}

\int_{0}^{2} (x (64 - (x + 3)^{3})) d x

\frac{d}{d x} ((x^{2} - x)^{3})

\frac{d}{d x} (\frac{1}{3} (x^{2} + 2)^{\frac{3}{2}} - 5)

\frac{d}{d x} (\frac{1}{sec ^{2} ( x )})

f (x) = \frac{2}{x + 1}, at x = 7

What is the solution for (2y+1)dx+((x^2-y)/x)dy=0 ?
The solution for (2y+1)dx+((x^2-y)/x)dy=0 is y=x^2-sqrt(x^4+x^2-c_{1)},y=x^2+sqrt(x^4+x^2-c_{1)}