What is the derivative of 1/(sec^2(x)) ?

The derivative of 1/(sec^2(x)) is -sin(2x)

What is the first derivative of 1/(sec^2(x)) ?

The first derivative of 1/(sec^2(x)) is -sin(2x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (\frac{1}{sec ^{2} ( x )})

- sin (2 x)

Solution steps

\frac{d}{d x} (\frac{1}{sec ^{2} ( x )})

Simplify

\frac{1}{sec ^{2} ( x )} : cos^{2} (x)

= \frac{d}{d x} (cos^{2} (x))

Apply the chain rule:

2 cos (x) \frac{d}{d x} (cos (x))

= 2 cos (x) \frac{d}{d x} (cos (x))

\frac{d}{d x} (cos (x)) = - sin (x)

= 2 cos (x) (- sin (x))

Simplify

2 cos (x) (- sin (x)) : - sin (2 x)

= - sin (2 x)

f (x) = \frac{2}{x + 1}, at x = 7

x \to 0 + lim (\frac{12}{x ^{2}})

\int_{0}^{2} \frac{x ^{2}}{2} d x

\int \frac{3}{4 x - x ^{2}} d x

\int \frac{2 x ^{2} + 2}{( x ^{2} - 2 x + 2 ) ^{2}} d x

What is the derivative of 1/(sec^2(x)) ?
The derivative of 1/(sec^2(x)) is -sin(2x)
What is the first derivative of 1/(sec^2(x)) ?
The first derivative of 1/(sec^2(x)) is -sin(2x)