What is (\partial)/(\partial x)(8arcsin(x^2)) ?

The answer to (\partial)/(\partial x)(8arcsin(x^2)) is (16x)/(sqrt(1-x^4))

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(\partial)/(\partial x)(8arcsin(x^2))

\frac{\partial}{\partial x} (8 arcsin (x^{2}))

\frac{16 x}{1 - x ^{4}}

Solution steps

\frac{\partial}{\partial x} (8 arcsin (x^{2}))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 8 \frac{\partial}{\partial x} (arcsin (x^{2}))

Apply the chain rule:

\frac{1}{1 - ( x ^{2} ) ^{2}} \frac{\partial}{\partial x} (x^{2})

= \frac{1}{1 - ( x ^{2} ) ^{2}} \frac{\partial}{\partial x} (x^{2})

\frac{\partial}{\partial x} (x^{2}) = 2 x

= 8 \cdot \frac{1}{1 - ( x ^{2} ) ^{2}} \cdot 2 x

Simplify

8 \cdot \frac{1}{1 - ( x ^{2} ) ^{2}} \cdot 2 x : \frac{16 x}{1 - x ^{4}}

= \frac{16 x}{1 - x ^{4}}

\frac{d y}{d x} = \frac{e ^{x} - 1}{e ^{y}}, f (1) = 0

7 x

\frac{3 x ^{\frac{3}{5}} - x}{x - 1}

\int \frac{x + 1}{x ^{2} + 2 x + 5} d x

What is (\partial)/(\partial x)(8arcsin(x^2)) ?
The answer to (\partial)/(\partial x)(8arcsin(x^2)) is (16x)/(sqrt(1-x^4))