What is the derivative of \sqrt[3]{n/4}+50 ?

The derivative of \sqrt[3]{n/4}+50 is (4^{2/3})/(12n^{2/3)}

What is the first derivative of \sqrt[3]{n/4}+50 ?

The first derivative of \sqrt[3]{n/4}+50 is (4^{2/3})/(12n^{2/3)}

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derivative of

\frac{4 ^{\frac{2}{3}}}{12 n ^{\frac{2}{3}}}

Solution steps

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

\frac{d}{d n} (50) = 0

= \frac{4 ^{\frac{2}{3}}}{12 n ^{\frac{2}{3}}} + 0

Simplify

= \frac{4 ^{\frac{2}{3}}}{12 n ^{\frac{2}{3}}}

\frac{\partial}{\partial x} (x e^{x^{2} y^{2}})

x \to 1 lim (b + \frac{1}{x - 1})

y = 4 x, y = \frac{4}{x}, x = 4

\frac{1}{s ( s ^{2} + 6 s + 13 )}

x \to 1 lim (10 x + 15)

What is the derivative of \sqrt[3]{n/4}+50 ?
The derivative of \sqrt[3]{n/4}+50 is (4^{2/3})/(12n^{2/3)}
What is the first derivative of \sqrt[3]{n/4}+50 ?
The first derivative of \sqrt[3]{n/4}+50 is (4^{2/3})/(12n^{2/3)}