What is area x=7y^2,x=5+2y^2 ?

The answer to area x=7y^2,x=5+2y^2 is No Solution

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area x=7y^2,x=5+2y^2

area

x = 7 y^{2}, x = 5 + 2 y^{2}

No Solution

Solution steps

Isolate

y

for

x = 7 y^{2} : y = \frac{x}{7}, y = - \frac{x}{7}

Isolate

y

for

x = 5 + 2 y^{2} : y = \frac{x - 5}{2}, y = - \frac{x - 5}{2}

f_{1} (x) = \frac{x}{7}

f_{2} (x) = - \frac{x}{7}

To find the intersection points solve

f_{i} (x) = f_{j} (x)

\frac{x}{7} = - \frac{x}{7} : x = 0

\frac{x}{7} = \frac{x - 5}{2} : x = 7

\frac{x}{7} = - \frac{x - 5}{2} :

No Solution for

x \in R

- \frac{x}{7} = \frac{x - 5}{2} :

No Solution for

x \in R

- \frac{x}{7} = - \frac{x - 5}{2} : x = 7

\frac{x - 5}{2} = - \frac{x - 5}{2} : x = 5

Curves not bounded

= No Solution

f (x) = 4 x, at x = 25

\frac{\partial}{\partial x} ((t + 1)^{3})

\frac{d}{d x} (sin (cos (x^{2})))

\int \frac{2 x ^{2} + 3}{( x ^{2} + 1 ) ^{2}} d x

(x + y) \frac{d y}{d x} = x - y

What is area x=7y^2,x=5+2y^2 ?
The answer to area x=7y^2,x=5+2y^2 is No Solution