What is (\partial)/(\partial x)(y^4 1/x) ?

The answer to (\partial)/(\partial x)(y^4 1/x) is -(y^4)/(x^2)

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(\partial)/(\partial x)(y^4 1/x)

\frac{\partial}{\partial x} (y^{4} \frac{1}{x})

- \frac{y ^{4}}{x ^{2}}

Solution steps

\frac{\partial}{\partial x} (y^{4} \frac{1}{x})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= y^{4} \frac{\partial}{\partial x} (\frac{1}{x})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= y^{4} \frac{\partial}{\partial x} (x^{- 1})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= y^{4} (- 1 \cdot x^{- 1 - 1})

Simplify

y^{4} (- 1 \cdot x^{- 1 - 1}) : - \frac{y ^{4}}{x ^{2}}

= - \frac{y ^{4}}{x ^{2}}

\int x sin (1 + x^{\frac{3}{2}}) d x

\int sin (6 π x) d x

\frac{\partial}{\partial x} (ln (\frac{2}{x}))

x^{2} y^{^{''}} + x y^{^{'}} - y = 2 x

- \frac{6}{x ^{7}}

What is (\partial)/(\partial x)(y^4 1/x) ?
The answer to (\partial)/(\partial x)(y^4 1/x) is -(y^4)/(x^2)