What is the solution for x^2y^{''}+xy^'-y=2x ?

The solution for x^2y^{''}+xy^'-y=2x is y=c_{1}x+(c_{2})/x+xln(x)-x/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^2y^{''}+xy^'-y=2x

x^{2} y^{^{''}} + x y^{^{'}} - y = 2 x

y = c_{1} x + \frac{c _{2}}{x} + x ln (x) - \frac{x}{2}

Solution steps

x^{2} y^{''} (x) + x y^{'} (x) - y = 2 x

Solve linear ODE:

y = c_{1} x + \frac{c _{2}}{x} + x ln (x) - \frac{x}{2}

y = c_{1} x + \frac{c _{2}}{x} + x ln (x) - \frac{x}{2}

- \frac{6}{x ^{7}}

\int \frac{1}{( x - 1 ) ( x - 3 )} d x

\frac{d}{d x} (sin (\frac{3}{x}))

x \to 2 lim (\frac{x}{x + 2})

\frac{d}{d x} ((x^{2} + 1)^{3})

What is the solution for x^2y^{''}+xy^'-y=2x ?
The solution for x^2y^{''}+xy^'-y=2x is y=c_{1}x+(c_{2})/x+xln(x)-x/2