What is the derivative of (x^2+1^3) ?

The derivative of (x^2+1^3) is 6x(x^2+1)^2

What is the first derivative of (x^2+1^3) ?

The first derivative of (x^2+1^3) is 6x(x^2+1)^2

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\frac{d}{d x} ((x^{2} + 1)^{3})

6 x (x^{2} + 1)^{2}

Solution steps

\frac{d}{d x} ((x^{2} + 1)^{3})

Apply the chain rule:

3 (x^{2} + 1)^{2} \frac{d}{d x} (x^{2} + 1)

= 3 (x^{2} + 1)^{2} \frac{d}{d x} (x^{2} + 1)

\frac{d}{d x} (x^{2} + 1) = 2 x

= 3 (x^{2} + 1)^{2} \cdot 2 x

Simplify

= 6 x (x^{2} + 1)^{2}

x \to - \infty lim (\frac{4 e ^{\frac{1}{x}} - 1}{1 + e ^{x}})

y = cos (x) sin (x)

\int \frac{2}{x ^{2} - 3 x + 2} d x

\frac{\partial}{\partial x} (cos (x + 8 y))

What is the derivative of (x^2+1^3) ?
The derivative of (x^2+1^3) is 6x(x^2+1)^2
What is the first derivative of (x^2+1^3) ?
The first derivative of (x^2+1^3) is 6x(x^2+1)^2