What is the limit as x approaches 2 of 1/((x^2-4)) ?

The limit as x approaches 2 of 1/((x^2-4)) is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 2 of 1/((x^2-4))

x \to 2 lim (\frac{1}{( x ^{2} - 4 )})

diverges

Solution steps

x \to 2 lim (\frac{1}{x ^{2} - 4})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 2 + lim (\frac{1}{x ^{2} - 4}) = \infty

x \to 2 - lim (\frac{1}{x ^{2} - 4}) = - \infty

= diverges

x \to 0 + lim ((- 2 ln (x))^{x})

x \to 0 lim (3 x ln (\frac{1}{x}))

x \to 0 lim (\frac{ln ( x ^{4} )}{x})

x \to + 0 lim (s g (s, x) n (x))

x \to 4 lim (f (x) x)

What is the limit as x approaches 2 of 1/((x^2-4)) ?
The limit as x approaches 2 of 1/((x^2-4)) is diverges