What is (\partial)/(\partial x)(cos(x)sin(yz)) ?

The answer to (\partial)/(\partial x)(cos(x)sin(yz)) is -sin(yz)sin(x)

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(\partial)/(\partial x)(cos(x)sin(yz))

\frac{\partial}{\partial x} (cos (x) sin (yz))

- sin (yz) sin (x)

Solution steps

\frac{\partial}{\partial x} (cos (x) sin (yz))

Treat

y, z

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= sin (yz) \frac{\partial}{\partial x} (cos (x))

Apply the common derivative:

\frac{\partial}{\partial x} (cos (x)) = - sin (x)

= sin (yz) (- sin (x))

Simplify

= - sin (yz) sin (x)

\frac{d}{d x} (139 + \frac{36}{x} + \frac{x ^{2}}{16})

\int \frac{x ^{2}}{5 + x} d x

\int 13 lo g_{15} (x) d x

\int (x^{2} + x) \cdot e^{2 x} d x

\int - \frac{e ^{2 x}}{1 + e ^{x}} d x

What is (\partial)/(\partial x)(cos(x)sin(yz)) ?
The answer to (\partial)/(\partial x)(cos(x)sin(yz)) is -sin(yz)sin(x)