What is the limit as x approaches pi of ln(sin(x/2)) ?

The limit as x approaches pi of ln(sin(x/2)) is 0

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limit as x approaches pi of ln(sin(x/2))

x \to π lim (ln (sin (\frac{x}{2})))

0

Solution steps

x \to π lim (ln (sin (\frac{x}{2})))

Plug in the value

x = π

= ln (sin (\frac{π}{2}))

Simplify

ln (sin (\frac{π}{2})) : 0

= 0

x \to \frac{π}{2} lim (1 + cos (x))

x \to 1 lim (e^{\frac{x}{x - 1}})

x \to 0 lim (x^{2} + 7 x + 5)

x \to \infty lim (x - \frac{16}{3})

x \to 0 + lim ((1 - 6 x)^{\frac{5}{x}})

What is the limit as x approaches pi of ln(sin(x/2)) ?
The limit as x approaches pi of ln(sin(x/2)) is 0