What is the limit as x approaches 0 of (4x-1)/x ?

The limit as x approaches 0 of (4x-1)/x is diverges

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limit as x approaches 0 of (4x-1)/x

x \to 0 lim (\frac{4 x - 1}{x})

diverges

Solution steps

x \to 0 lim (\frac{4 x - 1}{x})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (\frac{4 x - 1}{x}) = - \infty

x \to 0 - lim (\frac{4 x - 1}{x}) = \infty

= diverges

x \to 0 + lim (ln (x) ln (1 - x))

x \to 2 lim (\frac{5}{4 x - 8})

x \to 7 lim (13)

x \to - 1 lim (- x + 8)

x \to 0 lim ((1 + x^{2})^{3})

What is the limit as x approaches 0 of (4x-1)/x ?
The limit as x approaches 0 of (4x-1)/x is diverges