What is the limit as x approaches pi/2 of 5xsin(x) ?

The limit as x approaches pi/2 of 5xsin(x) is 5*pi/2

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limit as x approaches pi/2 of 5xsin(x)

x \to \frac{π}{2} lim (5 x sin (x))

5 \cdot \frac{π}{2}

Decimal Notation

7.85398 \dots

Solution steps

x \to \frac{π}{2} lim (5 x sin (x))

Plug in the value

x = \frac{π}{2}

= 5 \cdot \frac{π}{2} sin (\frac{π}{2})

Simplify

5 \cdot \frac{π}{2} sin (\frac{π}{2}) : 5 \cdot \frac{π}{2}

= 5 \cdot \frac{π}{2}

x \to - 3 lim (1 - x)

x \to 0 lim (\frac{1 cos ( x )}{x})

x \to (\frac{π}{2}) - lim (f (x))

x \to \frac{π}{3} lim (1 - 2 cos (x))

x \to 0 lim (+ (1 + \frac{1}{x})^{x})

What is the limit as x approaches pi/2 of 5xsin(x) ?
The limit as x approaches pi/2 of 5xsin(x) is 5*pi/2