What is the derivative of f(x)=2+x^2 ?

The derivative of f(x)=2+x^2 is 2x

What is the first derivative of f(x)=2+x^2 ?

The first derivative of f(x)=2+x^2 is 2x

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derivative of

f (x) = 2 + x^{2}

2 x

Solution steps

\frac{d}{d x} (2 + x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2) + \frac{d}{d x} (x^{2})

\frac{d}{d x} (2) = 0

\frac{d}{d x} (x^{2}) = 2 x

= 0 + 2 x

Simplify

= 2 x

n = 0 \sum \infty \frac{n x ^{n}}{n + 1}

\frac{\partial}{\partial y} (y e^{x^{2} - y})

\int x (sin (x^{\frac{3}{2}} - 1))^{2} d x

\frac{d}{d x} ((2 x^{2} - 7 x + 6)^{2})

7

What is the derivative of f(x)=2+x^2 ?
The derivative of f(x)=2+x^2 is 2x
What is the first derivative of f(x)=2+x^2 ?
The first derivative of f(x)=2+x^2 is 2x